Advantages and Disadvantages of Array in C
An array is a data structure that stores a collection of elements, all of the same data type, in a contiguous block of memory. Each element in the array is identified by an index, which is a numerical value that represents the position of the element in the array. The first element in the array has an index of 0, the second element has an index of 1, and so on.
Arrays can be used to store a variety of data types, including integers, floats, characters, and even user-defined types. They are commonly used to store collections of similar data, such as a list of numbers, a list of strings, or a list of objects.
Though, the array got its own set of advantages and disadvantages.
Advantages of Arrays
Below are some advantages of the array:
- In an array, accessing an element is very easy by using the index number.
- The search process can be applied to an array easily.
- 2D Array is used to represent matrices.
- For any reason a user wishes to store multiple values of similar type then the Array can be used and utilized efficiently.
- Arrays have low overhead.
- C provides a set of built-in functions for manipulating arrays, such as sorting and searching.
- C supports arrays of multiple dimensions, which can be useful for representing complex data structures like matrices.
- Arrays can be easily converted to pointers, which allows for passing arrays to functions as arguments or returning arrays from functions.
Disadvantages of Arrays
Now let’s see some disadvantages of the array and how to overcome it:
Array size is fixed: The array is static, which means its size is always fixed. The memory which is allocated to it cannot be increased or decreased. Below is the program for the same:
C
// C program to illustrate that the // array size is fixed #include <stdio.h> // Driver Code int main() { int arr[10]; // Assign values to array arr[0] = 5; arr[5] = 6; arr[7] = -9; // Print array element at index 0 printf ( "Element at index 0" " is %d\n" , arr[0]); // Print array element at index 11 printf ( "Element at index 11" " is %d" , arr[11]); return 0; } |
Element at index 0 is 5 Element at index 11 is -1176897384
Explanation: In the above program the array of size 10 is declared and the value is assigned at a particular index. But when the value at index 11 is printed then it prints the garbage value because the array was accessed out of the bound index. In some compiler, it gives error as “Array Index Out Of Bound.”.
How to overcome: To overcome that problem use Dynamic Memory Allocation like malloc(), calloc(). It also helps us to deallocates the memory using the free() method which helps to reduce wastage of memory by releasing it. Below is the program for the same:
C
// C program to illustrate the use of // array using Dynamic Memory Allocation #include <stdio.h> #include <stdlib.h> // Driver Code int main() { // Pointer will hold the base address int * ptr; int n = 10; // Dynamically allocates memory // using malloc() function ptr = ( int *) malloc (n * sizeof ( int )); // Assign values to the array for ( int i = 0; i < n; i++) { ptr[i] = i + 1; } // Print the array printf ( "The elements are: " ); for ( int i = 0; i < n; i++) { printf ( "%d " , ptr[i]); } // Free the dynamically // allocated memory free (ptr); return 0; } |
The elements are: 1 2 3 4 5 6 7 8 9 10
Array is homogeneous:The array is homogeneous, i.e., only one type of value can be store in the array. For example, if an array type “int“, can only store integer elements and cannot allow the elements of other types such as double, float, char so on. Below is the program for the same:
C
// C++ program to illustrate that // the array is homogeneous #include <stdio.h> // Driver Code int main() { // Below declaration will give // Compilation Error int a[5] = { 0, 1, 2, "string" , 9, 4.85 }; return 0; } |
100 547.000000 Ram
Output:
Explanation: The above code gives “Compilation Error” as an integer type array is assigned value to a string and float type.
How to overcome: To overcome that problem, the idea is to structure, where it can store non-homogeneous (heterogeneous) value. Below is the program for the same:
C
// C program to illustrate the use of // structure to store heterogeneous // variables #include <stdio.h> // Structure students struct student { int student_id; float marks; char name[30]; }; // Driver Code int main() { // Structure variable s1 struct student s1 = { 100, 547, "Ram" }; // Accessing structure members // using structure pointer printf ( "%d\n" , s1.student_id); printf ( "%f\n" , s1.marks); for ( int i = 0; s1.name[i] != '\0' ; i++) { printf ( "%c" , s1.name[i]); } return 0; } |
100 547.000000 Ram
Array is Contiguous blocks of memory: The array stores data in contiguous(one by one) memory location. Below is the representation of the same:
How to overcome: To overcome the sequential access to the array, the idea is to use the Linked list. In a Linked list, the elements are not stored in contiguous memory locations. Below is the representation of the same:
Insertion and deletion are not easy in Array: The operation insertion and deletion over an array are problematic as to insert or delete anywhere in the array, it is necessary to traverse the array and then shift the remaining elements as per the operation. This operation cost is more.
Example: For inserting 22 in 3rd position of the array then below are the steps:
Below is the program to illustrate the same:
C
// C Program to insert an element at // a specific position in an array #include <stdio.h> // Driver Code int main() { int arr[100] = { 0 }; int i, x, pos, n = 10; // Initial array of size 10 for (i = 0; i < 10; i++) { arr[i] = i + 1; } // Print the original array for (i = 0; i < n; i++) { printf ( "%d " , arr[i]); } printf ( "\n" ); // Element to be inserted x = 50; // Position at which element // is to be inserted pos = 5; printf ( "Array after inserting %d" " at position %d\n" , x, pos); // Increase the size by 1 n++; // Shift elements forward for (i = n - 1; i >= pos; i--) { arr[i] = arr[i - 1]; } // Insert x at pos arr[pos - 1] = x; // Print the updated array for (i = 0; i < n; i++) { printf ( "%d " , arr[i]); } return 0; } |
1 2 3 4 5 6 7 8 9 10 Array after inserting 50 at position 5 1 2 3 4 50 5 6 7 8 9 10
How to overcome: To overcome the above problem using a Linked List. Below is the representation of the same:
Below is the program to implement the same:
C
// C program to insert an element at // a position using linked list #include <stdio.h> #include <stdlib.h> // Structure for the linked list struct node { int data; struct node* next; }; // head Node struct node* head; // Function to insert any element // at the end of the linked list int insert_last( int k) { struct node *ptr, *s; ptr = ( struct node*) malloc ( sizeof ( struct node)); ptr->data = k; ptr->next = NULL; // If head is NULL if (head == NULL) { head = ptr; } // Else else { s = head; // Traverse the LL to last while (s->next != NULL) { s = s->next; } s->next = ptr; } } // Function to display linked list void display() { struct node* s; // Store the head s = head; // Traverse till s is NULL while (s != NULL) { // Print the data printf ( "%d " , s->data); s = s->next; } printf ( "\n" ); } // Function to insert any element at // the given position of linked list int insert_position( int a, int b) { int f = 0, i; struct node *ptr, *s; // Allocate new Node ptr = ( struct node*) malloc ( sizeof ( struct node)); ptr->data = a; // If first position if (b == 1) { ptr->next = head; head = ptr; } // Otherwise else { s = head; // Move to (b - 1) position for (i = 0; i < b - 2; i++) { s = s->next; } // Assign node ptr->next = s->next; s->next = ptr; } return 0; } // Driver Code int main() { // Given Linked List insert_last(3); insert_last(1); insert_last(5); insert_last(7); printf ( "Current Linked List is: " ); // Display the LL display(); // Insert 6 at position 4 insert_position(6, 4); printf ( "\n Linked List after insert" " 6 in 4th position: " ); // Display the LL display(); return 0; } |
Current Linked List is: 3 1 5 7 Linked List after insert 6 in 4th position: 3 1 5 6 7