Find the XOR of first half and second half elements of an array
Given an array arr of size N. The task is to find the XOR of the first half (N/2) elements and second half elements (N – N/2) of an array.
Examples:
Input: arr[]={20, 30, 50, 10, 55, 15, 42}
Output: 56, 24
Explanation:
XOR of first half elements 20 ^ 30 ^ 50 is 56
Xor of second half elements 10 ^ 55 ^ 15 ^ 42 is 24
Input: arr[]={50, 45, 36, 6, 8, 87}
Output: 59, 89
Approach:
- Initialize FirstHalfXOR and SecondHalfXOR as 0.
- Traverse the array and XOR elements in FirstHalfXOR until the current index is less than N/2.
- Otherwise, XOR elements in SecondHalfXOR.
Below is the implementation of the above approach:
C++
// C++ program to find the xor of // the first half elements and // second half elements of an array #include <iostream> using namespace std; // Function to find the xor of // the first half elements and // second half elements of an array void XOROfElements( int arr[], int n){ int FirstHalfXOR = 0; int SecondHalfXOR = 0; for ( int i=0; i < n; i++){ // xor of elements in FirstHalfXOR if (i < n / 2) FirstHalfXOR ^= arr[i]; // xor of elements in SecondHalfXOR else SecondHalfXOR ^= arr[i]; } cout << FirstHalfXOR << "," << SecondHalfXOR << endl; } // Driver Code int main() { int arr[] = {20, 30, 50, 10, 55, 15, 42}; int N = sizeof (arr)/ sizeof (arr[0]); // Function call XOROfElements(arr, N); return 0; } // This code is contributed by AnkitRai01 |
Java
// Java program to find the xor of // the first half elements and // second half elements of an array class GFG{ // Function to find the xor of // the first half elements and // second half elements of an array static void XOROfElements( int arr[], int n){ int FirstHalfXOR = 0 ; int SecondHalfXOR = 0 ; for ( int i = 0 ; i < n; i++){ // xor of elements in FirstHalfXOR if (i < n / 2 ) FirstHalfXOR ^= arr[i]; // xor of elements in SecondHalfXOR else SecondHalfXOR ^= arr[i]; } System.out.print(FirstHalfXOR + "," + SecondHalfXOR + "\n" ); } // Driver Code public static void main(String[] args) { int arr[] = { 20 , 30 , 50 , 10 , 55 , 15 , 42 }; int N = arr.length; // Function call XOROfElements(arr, N); } } // This code is contributed by 29AjayKumar |
Python3
# Python3 program to find the xor of # the first half elements and # second half elements of an array # Function to find the xor of # the first half elements and # second half elements of an array def XOROfElements(arr, n): FirstHalfXOR = 0 ; SecondHalfXOR = 0 ; for i in range (n): # xor of elements in FirstHalfXOR if (i < n / / 2 ): FirstHalfXOR ^ = arr[i]; # xor of elements in SecondHalfXOR else : SecondHalfXOR ^ = arr[i]; print (FirstHalfXOR, "," ,SecondHalfXOR); # Driver Code arr = [ 20 , 30 , 50 , 10 , 55 , 15 , 42 ]; N = len (arr); # Function call XOROfElements(arr, N); |
C#
// C# program to find the xor of // the first half elements and // second half elements of an array using System; class GFG{ // Function to find the xor of // the first half elements and // second half elements of an array static void XOROfElements( int []arr, int n) { int FirstHalfXOR = 0; int SecondHalfXOR = 0; for ( int i = 0; i < n; i++) { // xor of elements in FirstHalfXOR if (i < n / 2) FirstHalfXOR ^= arr[i]; // xor of elements in SecondHalfXOR else SecondHalfXOR ^= arr[i]; } Console.Write(FirstHalfXOR + "," + SecondHalfXOR + "\n" ); } // Driver Code public static void Main(String[] args) { int []arr = { 20, 30, 50, 10, 55, 15, 42 }; int N = arr.Length; // Function call XOROfElements(arr, N); } } // This code is contributed by 29AjayKumar |
Javascript
<script> // Javascript program to find the xor of // the first half elements and // second half elements of an array // Function to find the xor of // the first half elements and // second half elements of an array function XOROfElements(arr , n) { var FirstHalfXOR = 0; var SecondHalfXOR = 0; for (i = 0; i < n; i++) { // xor of elements in FirstHalfXOR if (i < parseInt(n / 2)) FirstHalfXOR ^= arr[i]; // xor of elements in SecondHalfXOR else SecondHalfXOR ^= arr[i]; } document.write( FirstHalfXOR + ", " + SecondHalfXOR + "\n" ); } // Driver Code var arr = [ 20, 30, 50, 10, 55, 15, 42 ]; var N = arr.length; // Function call XOROfElements(arr, N); // This code contributed by umadevi9616 </script> |
Output:
56, 24
Time complexity: O(N), as we are using a loop to traverse the array.
Auxiliary Space: O(1), as we are not using any extra space.