Pandas Series dt.dayofyear | Get Day of Year in Pandas
Pandas dt.dayofyear attribute returns the ordinal day of the year in the underlying DateTime data in the given Series object.
Example:
Python3
import pandas as pd sr = pd.Series(['2012-10-21 09:30', '2019-7-18 12:30', '2008-02-2 10:30', '2010-4-22 09:25', '2019-11-8 02:22']) idx = ['Day 1', 'Day 2', 'Day 3', 'Day 4', 'Day 5'] sr.index = idx sr = pd.to_datetime(sr) result = sr.dt.dayofyear print(result) |
Output
Syntax
Syntax: Series.dt.dayofyear
Parameter: None
Returns: Series with integers indicating the day number
How to Get Day of Year for a Date in Pandas Series
To get the day number for a date in the Pandas Series we use the dt.dayofyear method of the Pandas Library in Python. It returns the ordinal day of the year for a date in the Series.
Let us understand it better with an example:
Example:
Use Series.dt.dayofyear attribute to return the ordinal day of the year in the underlying data of the given Series object.
Python3
# importing pandas as pd import pandas as pd # Creating the Series sr = pd.Series(pd.date_range('2012-12-12 12:12', periods = 5, freq = 'M')) # Creating the index idx = ['Day 1', 'Day 2', 'Day 3', 'Day 4', 'Day 5'] # set the index sr.index = idx # Print the series print(sr) |
Output :
Now we will use the Series.dt.dayofyear attribute to return the ordinal day of the year in the DateTime based data in the given series object.
Python3
# return the day of year result = sr.dt.dayofyear # print the result print(result) |
Output :
As we can see in the output, the dt.dayofyear attribute has successfully accessed and returned the day of the year in the underlying data of the given series object.