PYGLET – Getting Window Visible Status
In this article we will see how we can get the window visible status in PYGLET module in python. Pyglet is easy to use but powerful library for developing visually rich GUI applications like games, multimedia etc. A window is a “heavyweight” object occupying operating system resources. Windows may appear as floating regions or can be set to fill an entire screen (fullscreen).The window visible status is True is it is visible else it is False We can create a window with the help of command given below
pyglet.window.Window(width, height, title)
In order to create window we use visible attribute with the window object Syntax : window.visible Argument : It takes no argument Return : It returns bool
Below is the implementation
Python3
# importing pyglet module import pyglet import pyglet.window.key # width of window width = 500 # height of window height = 500 # caption i.e title of the window title = "w3wiki" # creating a window window = pyglet.window.Window(width, height, title) # text text = "w3wiki" # creating a label with font = times roman # font size = 36 # aligning it to the center label = pyglet.text.Label(text, font_name = 'Times New Roman' , font_size = 36 , x = window.width / / 2 , y = window.height / / 2 , anchor_x = 'center' , anchor_y = 'center' ) new_label = pyglet.text.Label(text, font_name = 'Times New Roman' , font_size = 10 , x = 25 , y = 25 ) # on draw event @window .event def on_draw(): # clearing the window window.clear() # drawing the label on the window label.draw() # key press event @window .event def on_key_press(symbol, modifier): # key "C" get press if symbol = = pyglet.window.key.C: # closing the window window.close() # image for icon img = image = pyglet.resource.image("logo.png") # setting image as icon window.set_icon(img) # getting window visible status value = window.visible # printing the value print ("Window Visible Status : ") print (value) # start running the application pyglet.app.run() |
Output :
Window Visible Status : True