Removing Element from Specified Index in Java Vector
Element at the specified index in Java vector can be removed using remove() method. this method is present in java.util.Vector class. We can pass index of the element which will be removed as an argument. remove() method return method returns the element that was removed.
Syntax :
public removed_element remove(int index)
Parameters: The index of the element to be removed.
Return Type: This method returns the element that was removed from the list.
Exception: This method throws IndexOutOfBoundsException if the index is out of range.
Code:
Java
// Java program for removing element // at specified index import java.util.Vector; public class GFG { public static void main(String arg[]) { // Create an Vector Vector<Integer> vector = new Vector<>(); // Add elements in the vector vector.add( 10 ); vector.add( 20 ); vector.add( 30 ); vector.add( 20 ); vector.add( 40 ); // display original vector System.out.println( "Values in vector: " + vector); // remove 2 index element and store the value in r int r = vector.remove(( 2 )); // display removed element System.out.println( "Removed element: " + r); // display vector after 2 index element System.out.println( "Values in vector: " + vector); } } |
Output
Values in vector: [10, 20, 30, 20, 40] Removed element: 30 Values in vector: [10, 20, 20, 40]
Exception in remove() method:
When we will try to remove an element at the index which is greater than or equal to the size of the array list, the editor will give us the IndexOutOfBound Exception on running.
Java
// Java program to show the exception // of remove() method import java.util.ArrayList; public class ArrayListDemo { public static void main(String[] args) { // create an empty array list with an initial capacity ArrayList<Integer> arrlist = new ArrayList<Integer>( 5 ); // use add() method to add elements in the deque arrlist.add( 26 ); arrlist.add( 18 ); arrlist.add( 31 ); arrlist.add( 42 ); System.out.println( "Size of list: " + arrlist.size()); // let us print all the elements available in list for (Integer number : arrlist) { System.out.println( "Number = " + number); } // Removes element at 5th position // which is not present in the list // and will therefore give IndexOutOfBound exception arrlist.remove( 4 ); System.out.println( "Now, Size of list: " + arrlist.size()); // let us print all the elements available in list for (Integer number : arrlist) { System.out.println( "Number = " + number); } } } |
Exception in thread "main" java.lang.IndexOutOfBoundsException: Index 4 out of bounds for length 4