Categories
28°C, New York
Home Interview TCS Placement Paper | MCQ 7

TCS Placement Paper | MCQ 7

TCS Placement Paper | MCQ 8

  1. The sticks of the same length are used to form a triangle as shown below. If 87 such sticks are used then how many triangles can be formed? a) 42 b) 43 c) 44 d) 45 
    Answer: b) 43
    Solution: As we can see the first triangle can be formed using 3 sticks. So we have 87 – 3 = 84 sticks left. So every next triangle can be formed using 2 sticks. So we have 84/2 = 42 triangles and 43 triangles in all.
  2. Find the next number in the series of 3, 12, 7, 26, 15, ? a) 54 b) 55 c) 64 d) 74 
    Answer: a) 54
    Solution: 3 * 2 + 1 = 7 12 * 2 + 2 = 26 7 * 2 + 1 = 15 26 * 2 + 2 = 54
  3. There is a toy gun that made 10 musical sounds. It makes 2 musical sounds after being defective. What is the probability that same musical sound would be produced 5 times consecutively? a) 1/16 b) 1/32 c) 1/48 d) 1/2 
    Answer: b) 1/32
    Solution: The probability of making the same sound every time = 1/2, So, 1/2^5 = 1/32 (answer)
  4. In how many possible ways you can write 3240 as a product of 3 positive integers? a) 320 b) 420 c) 350 d) 450 
    Answer: d) 450 ways
    Solution: First let’s prime factorize the number 3240 = Let the three positive numbers be x, y and z We have to distribute three 2’s to x, y and z ways in (3+3-1)C(3-1) = 5C2 ways = 10 ways We have to distribute four 3’s to x, y, z in (3+4-1)C(3-1) = 6C2 ways We have to distribute one 5 to x, y, z in 3 ways. The total number of ways = 10×15×3=450 ways.
  5. The marked price of a shirt was 40% less than the suggested retail price. Ram purchased the coat for half of the marked price at the 15th-anniversary sale. What per cent less than the suggested retail price did Ram pay? a) 70% b) 20% c) 60% d) 30% 
    Answer: a) 70%
    Solution: Let the retail price of the shirt be Rs. 100 So according to the question, the market price will be = 100*0.6 = 60 Purchased price of Ram = 60/2 = 30 which is 70% less than retail price.
  6. HCF of 2472, 1284 and a 3rd number, is 12. If their LCM is 8*9*5*103*107, then what is the number? a) 2^2*3^2*7^1 b) 2^2*3^2*5^1 c) 2^2*3^2*8103 d) None of the above. 
    Answer: b) 2^2×3^2×5^1
    Solution: 2472 = 1284 = HCF = LCM = HCF of the number is the highest number which divides all the numbers. So N should be a multiple of 22×3 LCM is the largest number that is divided by the given numbers. As LCM contains 32×5 these two are from N. So N = [Tex]$2^2×3^2×5^1$[Tex]
  7. An old man takes 30 minutes and a young man takes 20 minutes to walk from apartment to office. If one day the old man started at 10.00 AM and the young man at 10:05 AM from the apartment to office, when will they meet? a) 10:00 b) 10:15 c) 10.30 d) 10:45 
    Answer: b) 10:15
    Solution: Let the distance of the apartment from the office be 12 km So the speed of the old man = 12 / (1/2) hr = 24 km/hr The young man speed = 12 / (1/3) hr = 36 km/hr Since the old man started 5 minutes earlier, he covers 24 × (5/60) = 2 km in 5 minutes. Now the time taken to the young man to meets him = 2/(36-24) * 60 = 10 minutes So the time of meet = 10:05 + 10 = 10 hr 15 min or 10:15
  8. In the range of 112 to 375, how many 2’s are there? a) 312 b) 156 c) 159 d) 160 
    Answer: b) 156
    Solution: The total number of 2’s in the units place = (122, 132, 142 … 192), (201, 212, 222, … 292), (302, 312, … 372) = 8 + 10 + 8 = 26 2’s The total number of 2’s in tenth’s place = (120, 121, 122, …, 129) + (220, 221, …, 229) + (320, 321, …, 329) = 30 The total number of 2’s in hundred’s place = (200, 201, … 299) = 100. So the total number of 2’s between 112 and 375 = 26 + 30 + 100 = 156
  9. Ram walks 36 km partly at a speed of 4 km/hr and partly at 3 km/hr. If he had walked at a speed of 3km/hr when he had walked at 4 and 4 km/hr when he had walked at 3 he would have walked only 34 km. The time (in hours) spent by Ram in walking was a) 10 b) 5 c) 12 d) 8 
    Answer: a) 10
    Solution: Let Ram walk ‘x’ hrs at 4 km/hr, and ‘y’ hrs at 3 km/hr. Given, 4x + 3y = 36 3x + 4y = 34 Solving these two equations we get x + y = 10
  10. What will be the 55th word in the arrangement of the letters of the word PERFECT? a) CEPFRET b) CEPFERT c) CEPERFT d) CEPRFET 
    Answer: b) CEPFERT
    Solution: Let’s arrange the word PERFECT in dictionary order = CEEFPRT Here, CEE(4!)=24 CEF(4!)=24 CEPF(3!)=6 So the 55th word is CEPFERT.

Tags:
#interview-preparation #placement preparation #TCS #Placements #TCS

TCS Placement Paper | MCQ 8