Find the value of k for the equation 2k2 + 144 = 0
Complex numbers are those with the formula a + ib, where a and b are real numbers and I (iota) is the imaginary component and represents (-1), and are often represented in rectangle or standard form. 10 + 5i, for example, is a complex number in which 10 represents the real component and 5i represents the imaginary part. Depending on the values of a and b, they might be wholly real or purely fictitious. When a = 0 in a + ib, ib is a totally imaginary number, and when b = 0, we get a, which is a strictly real number.
Some Powers of i
- i =
- i2 = β1
- i3 = i Γ i2 = i Γ β1 = βi
- i4 = i2 Γ i2 = β1 Γ β1 = 1
Find the value of k for the equation 2k2 + 144 = 0.
Solution:
2k2 + 144 = 0
β 2k2 = β144
β k2 = β72
β k =
β k =
β k =
β k = 6β2i
Similar Problems
Question 1. Find k if 2k2 + 64 = 0.
Solution:
2k2 + 64 = 0
β 2k2 = β64
β k2 = β32
β k =
β k =
β k =
β k = 4β2i
Question 2. Find k if 2k2 + 36 = 0.
Solution:
2k2 + 36 = 0
β 2k2 = β36
β k2 = β18
β k =
β k =
β k =
β k = 3β2i
Question 3. Find k if 2k2 + 400 = 0.
Solution:
2k2 + 400 = 0
β 2k2 = β400
β k2 = β200
β k =
β k =
β k =
β k = 10β2i
Question 4. Find k if 2k2 + 100 = 0.
Solution:
2k2 + 100 = 0
β 2k2 = β100
β k2 = β50
β k =
β k =
β k =
β k = 5β2i
Question 5. Find k if 2k2 + 256 = 0.
Solution:
2k2 + 256 = 0
β 2k2 = β256
β k2 = β128
β k =
β k =
β k =
β k = 8β2i