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Armstrong Number

1. Using Brute-force Approach

A number “N” is an Armstrong number if “N” is equal to the sum of all N’s digits raised to the power of the number of digits in N.

Example:

 

There are 2 ways to find all the Armstrong numbers between 1 to 1000 in C++:

  1. Using the Brute-force approach.
  2. Using the optimized solution.

Let’s start discussing each of these in detail.

C++ Program to Print Armstrong Numbers Between 1 to 1000

Here, we will see how to print Armstrong numbers between 1 to 1000 using a C++ program. 

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Armstrong Number

A number “N” is an Armstrong number if “N” is equal to the sum of all N’s digits raised to the power of the number of digits in N....

1. Using Brute-force Approach

The idea is to first count the number of digits (or find order). Let the number of digits be order_n. For every digit curr in input number num, compute currorder_n. If the sum of all such values is equal to num, then return true, else false....

2. Using Optimized Solution

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#C Basic Programs #C++ #C++ Programs #CPP

1. Using Brute-force Approach