Count the occurrence of a certain item in an array using sum()

Count the occurrence of a certain item in an array using count_nonzero()

Counting the matching value to count the occurrence of an item

A True is equivalent to 1 in Python, so usually add the True or non-zero values in the array to get the sum of values in the array that matches the condition.

Python3

import numpy as np
 
arr = np.array([2, 3, 4, 5, 3, 3, 5, 4, 7, 8, 3])
 
print('Numpy Array:')
print(arr)
 
# Count '3' in array
count = (arr == 3).sum()
 
print('Occurrences of "3" in array: ', count)

Output:

Numpy Array: 
[2 3 4 5 3 3 5 4 7 8 3] 
Occurrences of "3" in array: 4

Count the occurrence of a certain item in an ndarray – Numpy

In this article, the task is to find out how to count the occurrence of a certain item in an nd-Array in Python.

Example

Array = [[ 0  1  2  3]
        [ 4  5  2  7]  
        [ 8  2 10 11]]
        
Input: element = 2

Output: 3 times

Tags:

#Python #Python Programs #python

Count the occurrence of a certain item in an array using count_nonzero()

Counting the matching value to count the occurrence of an item

Count the occurrence of a certain item in an array using sum()

Python3

Count the occurrence of a certain item in an ndarray – Numpy

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