Efficiency of Generator
Efficiency of DC machines. When running as a generator, the load current (Amp) is supplied at the load voltage (volts).
Generator output = V IL – Watts.
Armature copper loss = Ia2 Ra.
For generator: Ia = IL + ISh.
Therefore, armature copper loss = (IL + ISh)2 Ra.
Constant loss: PC = V I0 – (I0 – ISh)2 Ra.
Therefore, total losses in the generator = PT = PC + (IL + ISh)2 Ra.
PT = V I0 – (I0 – ISh)2 Ra + (IL + ISh)2 Ra.
Input = output + all losses.
Input = V IL + PT, indicating generator efficiency.
Generator Efficiency
ηg = Output / Input x 100
ηg = ( V IL ) / ( V IL + PT ) x 100%
Swinburne Test of DC Machine
The Swinburne Test is a method for determining the performance characteristics of direct current (DC) devices like generators and motors. This test, named for its author, Thomas Swinburne, a renowned electrical engineer from the early twentieth century, gives useful information on the efficiency and overall health of DC equipment. If you are interested in electrical engineering, particularly DC machines, this test is very important. In this essay, we will go over the Swinburne Test, including its aim, methodology, and significance in the evaluation of direct current machines.
Table of Content
- Swinburne’s Test
- Calculation of Efficiency
- Efficiency of Motor
- Efficiency of Generator
- Swinburne’s Test Vs Hopkinson’s Test
- Advantages and Disadvantages
- Applications