How to use min() + lambda In Python

Method 3:Using a lambda function and the min() function

The combination of above functions offer shorthand to solve this problem. In this, we use min() to find minimum element difference and lambda function is used to perform iterations and computations.

Python

# Python3 code to demonstrate working of 
# Closest Pair to Kth index element in Tuple
# Using min() + lambda

# initializing list
test_list = [(3, 4), (78, 76), (2, 3), (9, 8), (19, 23)]

# printing original list
print("The original list is : " + str(test_list))

# initializing tuple
tup = (17, 23)

# initializing K 
K = 1

# Closest Pair to Kth index element in Tuple
# Using min() + lambda
res = min(range(len(test_list)), key = lambda sub: abs(test_list[sub][K - 1] - tup[K - 1]))

# printing result 
print("The nearest tuple to Kth index element is : " + str(test_list[res]))

Output

The original list is : [(3, 4), (78, 76), (2, 3), (9, 8), (19, 23)]
The nearest tuple to Kth index element is : (19, 23)

Time complexity: O(n), where n is the length of the input list
Auxiliary space: O(1), since we are not using any additional data structures or variables proportional to the size of the input list.

Python – Closest Pair to Kth index element in Tuple

In the given problem, condition K specifies the maximum allowable difference between corresponding elements of tuples, i.e., it represents the proximity threshold for finding the nearest tuple. The goal is to find the tuple in the list whose elements have the smallest maximum difference compared to the given tuple tup, and this difference should not exceed KKK.

Input : test_list = [(3, 4), (78, 76), (2, 3), (9, 8), (19, 23)] tup = (17, 23) K = 2
Output : (19, 23)

Input : test_list = [(3, 4, 9), (5, 6, 7)] tup = (1, 2, 5) K = 3
Output : (5, 6, 7)