How to use the seq() function In R Language

Example 1: 

R




# creating date_1 variable and
# storing date in it.
date_1<-as.Date("2020-08-10")
  
# creating date_2 variable and
 #storing date in it.
date_2<-as.Date("2023-10-10")
  
# Here first date will start from
# 2020-08-10 and end by 2023-10-10.
# Here increment is done by year.
# This three dates will be generated
# as we used eq and this dates will
# be stored in a.
a = seq(from = date_1, to = date_2, by = 'year')
print(a)
# Here we are finding length of a and
# we are subtracting 1 because we dont
# need to include current year.
print(length(a)-1)


Output:

[1] "2020-08-10" "2021-08-10" "2022-08-10" "2023-08-10"
[1] 3

Example 2:

R




# creating date_1 variable and
# storing date in it.
date_1<-as.Date("2020-08-10")
 
# creating date_2 variable and
# storing date in it.
date_2<-as.Date("2100-08-10")
 
# Here first date will start from
# 2020-08-10 and end by 2100-08-10.
# Here increment is done by year.
# This three dates will be generated
# as we used seq and this dates will
# be stored in a.
a = seq(from = date_1, to = date_2, by = 'year')
print(a)
# Here we are finding length of a and
# we are subtracting 1 because we dont
# need to include current year.
print(length(a)-1)


 Output:

[1] "2020-08-10" "2021-08-10" "2022-08-10" "2023-08-10" "2024-08-10"
[6] "2025-08-10" "2026-08-10" "2027-08-10" "2028-08-10" "2029-08-10"
[11] "2030-08-10" "2031-08-10" "2032-08-10" "2033-08-10" "2034-08-10"
[16] "2035-08-10" "2036-08-10" "2037-08-10" "2038-08-10" "2039-08-10"
[21] "2040-08-10" "2041-08-10" "2042-08-10" "2043-08-10" "2044-08-10"
[26] "2045-08-10" "2046-08-10" "2047-08-10" "2048-08-10" "2049-08-10"
[31] "2050-08-10" "2051-08-10" "2052-08-10" "2053-08-10" "2054-08-10"
[36] "2055-08-10" "2056-08-10" "2057-08-10" "2058-08-10" "2059-08-10"
[41] "2060-08-10" "2061-08-10" "2062-08-10" "2063-08-10" "2064-08-10"
[46] "2065-08-10" "2066-08-10" "2067-08-10" "2068-08-10" "2069-08-10"
[51] "2070-08-10" "2071-08-10" "2072-08-10" "2073-08-10" "2074-08-10"
[56] "2075-08-10" "2076-08-10" "2077-08-10" "2078-08-10" "2079-08-10"
[61] "2080-08-10" "2081-08-10" "2082-08-10" "2083-08-10" "2084-08-10"
[66] "2085-08-10" "2086-08-10" "2087-08-10" "2088-08-10" "2089-08-10"
[71] "2090-08-10" "2091-08-10" "2092-08-10" "2093-08-10" "2094-08-10"
[76] "2095-08-10" "2096-08-10" "2097-08-10" "2098-08-10" "2099-08-10"
[81] "2100-08-10"
[1] 80

How to calculate Years between Dates in R ?

To calculate the number of years between two dates we have several methods. In this article, we will discuss all the methods and their examples of how to calculate the number of years or the difference of years between two dates in the R Programming Language.

Table of Content

  • Method 1: Using the seq() function
  • Method 2: Using the difftime function
  • Method 3: Using the base R as.POSIXlt function

Example:

Input: 

Date_1 = 2020/02/21

Date_2 = 2023/03/21

Output:

3

Explanation: 

In Date_1 and Date_2 have three years difference in year.

Here we will use the seq() function to get the result. This function is used to create a sequence of elements in a Vector.

Syntax: 

length(seq(from=date_1, to=date_2, by=’year’)) -1  

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Method 1: Using the seq() function

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Method 2: Using the difftime function

Example 1:...

Method 3: Using the base R as.POSIXlt function

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