Python Program for Coin Change using Recursion

Recurrence Relation:

count(coins,n,sum) = count(coins,n,sum-count[n-1]) + count(coins,n-1,sum)

For each coin, there are 2 options.

  • Include the current coin: Subtract the current coin’s denomination from the target sum and call the count function recursively with the updated sum and the same set of coins i.e., count(coins, n, sum – coins[n-1] )
  • Exclude the current coin: Call the count function recursively with the same sum and the remaining coins. i.e., count(coins, n-1,sum ).

The final result will be the sum of both cases.

Base case:

  • If the target sum (sum) is 0, there is only one way to make the sum, which is by not selecting any coin. So, count(0, coins, n) = 1.
  • If the target sum (sum) is negative or no coins are left to consider (n == 0), then there are no ways to make the sum, so count(sum, coins, 0) = 0.
  • Coin Change | DP-7

Below is the Implementation of the above approach:

Python3




# Recursive Python3 program for
# coin change problem.
 
# Returns the count of ways we can sum
# coins[0...n-1] coins to get sum "sum"
 
 
def count(coins, n, sum):
 
    # If sum is 0 then there is 1
    # solution (do not include any coin)
    if (sum == 0):
        return 1
 
    # If sum is less than 0 then no
    # solution exists
    if (sum < 0):
        return 0
 
    # If there are no coins and sum
    # is greater than 0, then no
    # solution exist
    if (n <= 0):
        return 0
 
    # count is sum of solutions (i)
    # including coins[n-1] (ii) excluding coins[n-1]
    return count(coins, n - 1, sum) + count(coins, n, sum-coins[n-1])
 
 
# Driver program to test above function
coins = [1, 2, 3]
n = len(coins)
print(count(coins, n, 5))
 
# This code is contributed by Smitha Dinesh Semwal


Output

5 

Time Complexity: O(2sum)
Auxiliary Space: O(sum)

Python Program for Coin Change | DP-7

Write a Python program for a given integer array of coins[ ] of size N representing different types of denominations and an integer sum, the task is to find the number of ways to make a sum by using different denominations.

Examples:

Input: sum = 4, coins[] = {1,2,3},
Output: 4
Explanation: there are four solutions: {1, 1, 1, 1}, {1, 1, 2}, {2, 2}, {1, 3}.

Input: sum = 10, coins[] = {2, 5, 3, 6}
Output: 5
Explanation: There are five solutions: {2,2,2,2,2}, {2,2,3,3}, {2,2,6}, {2,3,5} and {5,5}.

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