Sample Problems on Permittivity of Free Space
Some sample problems based on the formula discussed in the article are:
Problem 1: The relative permittivity εr of a material between the plates of a capacitor is 5. If the permittivity of free space ε₀ is 8.854 ×10-12 F/m, find the permittivity i.e., ε of the material.
Solution:
Using the formula εr = ε/ε₀, we can rearrange it to find ε:
⇒ ε = εr × ε₀
Substitute the given values:
⇒ ε = 5 × 8.854 × 10-12 F/m
⇒ ε = 4.427 × 10-11 F/m
Thus, the required value of permittivity is 4.427 × 10-11 F/m
Problem 2: A capacitor with a relative permittivity of 3 is placed in a vacuum. Calculate the permittivity of the material between the plates.
Solution:
Using the formula εr = ε/ε₀, we can rearrange it to find ε:
⇒ ε = εr × ε₀
Substitute the given values:
⇒ ε = 3 × 8.854 × 10-12 F/m
⇒ ε = 2.656 × 10-11 F/m
Thus, the required value of permittivity is 2.656 × 10-11 F/m.
Permittivity of Free Space
Permittivity of Free Space or Permittivity of Vacuum is the property of material that measures the material’s ability to resist the formation of an electric field within it or to permit the passage of electric flux in a vacuum, as the resistivity offered by the free space is the lowest.
Permittivity of Free Space is introduced to students in class 12. In this article, we will explore the concept of Permittivity of Free Space in detail, including its definition, value, and formula.
Table of Content
- What is Permittivity?
- What is Permittivity of Free Space?
- What is the Value of Permittivity of Free Space?
- Permittivity of Free Space Formula
- Problems on Permittivity of Free Space
- Practice Problems on Permittivity of Free Space