Solved Example of Sinusoidal Steady State Analysis
Q. Equation of sinusoidal of wave form v(t) = 13 cos (50t + 10o) so find the amplitude ,frequency and period. Solve it.
On comparing [Tex]v(t)=Vmcos(wt+\phi) [/Tex]
So, Vm (amplitude)=13
Vphase:= 10
angular frequency [Tex] (\omega) [/Tex]=50 rad/secT
= [Tex]2 x \pi/\omega [/Tex]=2 x 3.414/50 =0.126
frequency = 1/0.126 = 7.96 Hz.
Sinusoidal Steady State Analysis – Electric circuits
In steady state (the fully charged state of the cap), current through the capacitor becomes zero. The sinusoidal steady-state analysis is a key technique in electrical engineering, specifically used to investigate how electric circuits respond to sinusoidal AC (alternating current) signals. This method simplifies the intricate details involved in time-varying AC circuits by representing voltages and currents as phasors—complex quantities that succinctly convey both amplitude and phase information.
Table of Content
- Sinusoidal Steady State Analysis
- Sinusoidal Source
- Derivation
- V-I Relation for an Inductor
- V-I Relationship for a Capacitor
- Frequency Response
- Bode Plots
- Examples