Solved Example on Magnetic Field Strength
Example 1: Find the MFS of a 2 m long solenoid of 2000 loops carrying a current of 1600 A.
Solution:
B = μ0nI
n = 2000/2
= 1000
Now,
B = (4π x 10−7 T m/A)(1000 m−1)(1600 A)
= 2.01 T
Example 2: Find the MFS of a 5 m long solenoid of 800 loops carrying a current of 1700 A.
Solution:
B = μ0NI
n = 800/5
= 160
Now,
B = (4π x 10−7 T m/A)(160 m-1)(1700 A)
= 0.314 T
Example 3: Find the MFS of a 12 m long solenoid of 700 loops carrying a current of 800 A.
Solution:
B = μ0NI
n = 700/12
= 58.33
B = (4π x 10−7 T m/A)(58.33 m-1)(800 A)
= 0.05864 T
Magnetic Field Strength
Magnetic field is defined as the region around a magnet which influences the other magnets. i.e. If we place a test magnet near a powerful magnet it experiences some force due to the powerful magnet the region close to the powerful magnet is called the magnetic field of the magnet. It is similar to the electric field of the charged particle and is represented by the magnetic field lines. The denser the magnetic field lines the higher the strength of the magnetic field.
Table of Content
- What is a Magnetic Field?
- Magnetic Field Strength Formula
- History of Magnetic Field
- Representation of Magnetic Field
- Properties of Magnetic Field Lines
- Magnetic Field Intensity
- How does a Magnetic Field Originate?
- Magnetic Field created by a Current Carrying Conductor
- Motion of Electrons around the Nuclei of Atoms
- Magnetic Field by Motion of Electrons around the Nuclei of Atoms
- Solved Example on Magnetic Field Strength
Let’s learn about magnetic field lines formula, derivation, and others in detail in this article.