Solved Problems on Laws of Friction

Problem 1: A boy is pulling a box of mass 10 kg. Identify the standard force. Furthermore, calculate the same force of friction if the coefficient of friction is 0.3.

Solution:

Given: Mass, m = 10 kg, where kg indicates kilogram.

Normal force, F_n =?

The mathematical expression for normal force is had by F_n = m g.

= 10 n kg × 9.8 m/ s2

= 98 N.

The Friction force is described as (μ F_n), where μ (m) is a coefficient of friction.

F = – 0.3 × 98N.

= 29.4 N.

Problem 2: Nancy who has a mass of 22lb is skating on the frost. The slider is assumed to be sliding on a frictionless floor if the kinetic coefficient of friction is 0.45. Discover the frictional force impacting her when it kisses the frost layer.

Solution:

Given: The mass m = 40 Kg, representation of the body, is the one that is subjected to the acceleration on a planet similar to ours.

The Friction coefficient μ=0.3,

The reason that F_n = mg is standard force is that it is the weight of an object which is measured by m x g.

Mr. Schumacher was accelerating with a force of 40 Kg × 9.8 m/s2.

= 392 N.

The force of Friction is demonstrated by F_f = μ Fn.

= 178 N = 0.45 × 392 N

= 176.4 N.

Friction is a fundamental force that affects our everyday lives. When we slide a book across a table or walk on a slippery surface, friction comes into play. There are various laws which govern the phenomenon of friction such as Amonton’s and Columnb’s Laws. In this article, we will discuss all the laws which help us understand the concept of Friction.