Square root an integer using built-in functions
Below is the implementation for finding the square root using the built-in function.
Python3
def countSquares(x): sqrt = x**0.5 result = int(sqrt) return resultx = 9print(countSquares(x)) |
3
Time Complexity: O(log(X))
Auxiliary Space: O(1)
Square Root Of Given Number using numpy.sqrt()
To find the square root of a number using Numpy, you can use the numpy.sqrt() function. This function takes in a number or an array of numbers and returns the square root of each element.
Here is an example of how you can use numpy.sqrt() to find the square root of a number:
Python3
import numpy as np# Find the square root of 9sqrt_9 = np.sqrt(9)print(sqrt_9) # Output: 3.0# Find the square root of a list of numbersnumbers = [4, 9, 16, 25]sqrt_numbers = np.sqrt(numbers)print(sqrt_numbers) # Output: [2.0 3.0 4.0 5.0] |
Output:
3.0
[2. 3. 4. 5.]
Note that numpy.sqrt() returns a Numpy array if the input is an array, and a single value if the input is a single number.
Time Complexity: The time complexity of the np.sqrt() function is O(1) for a single input and O(n) for an array of inputs, because it involves computing the square root of the input values. The time complexity is constant for a single input and linear in the size of the array for an array of inputs.
Space Complexity: The space complexity of the np.sqrt() function is O(1) for both a single input and an array of inputs, because it does not use any additional data structures and the space it uses is independent of the input size. The function returns a single value for a single input and an array of values for an array of inputs.
There can be many ways to solve this problem. For example, the Babylonian Method is one way. Please refer complete article on the Square root of an integer for more details!
Python Program To Find Square Root Of Given Number
Given an integer X, find its square root. If X is not a perfect square, then return floor(√x).
Examples:
Input: x = 4
Output: 2
Explanation: The square root of 4 is 2.Input: x = 11
Output: 3
Explanation: The square root of 11 lies in between 3 and 4 so floor of the square root is 3.