How to use the Built-in Parse Method In JSON

This approach leverages the parse() the method provided by the JSON library in Scala.

Syntax:

val jsonObject = Json.parse(jsonString)

The parse method parses the JSON string and returns a JSON object.

Below is the Scala program to convert a JSON string to a JSON object using the built-in parse method:

Scala
import play.api.libs.json.Json;

val jsonString = "{\"name\": \"John\", \"age\": 30}";
val jsonObject = Json.parse(jsonString);
println(jsonObject)

Output:


Using the Built-in Parse Method


How to Convert JSON String to a JSON Object in Scala?

When working with JSON data in Scala, we may often need to convert a JSON string into a JSON object. This can be useful for parsing and manipulating JSON data effectively. This article focuses on discussing ways to convert JSON string to a JSON object.

Table of Content

  • Using the Built-in Parse Method
  • Using the Read Method
  • Using the Jackson library
  • Using the Circe library
  • Conclusion

Similar Reads

Using the Built-in Parse Method

This approach leverages the parse() the method provided by the JSON library in Scala....

Using the Read Method

This approach utilizes the read method from the Json library to read the JSON string and convert it into a JSON object....

Using the Jackson Library

This approach involves using the Jackson library for JSON processing in Scala. The readTree method from the ObjectMapper class is used to parse the JSON string and create a JSON object....

Using the Circe Library

This approach utilizes the Circe library, which is a JSON library for Scala....

Conclusion

Converting JSON strings to JSON objects in Scala is a common task when dealing with JSON data. By using the methods provided by libraries like Json, Jackson, and Circe, developers can efficiently parse JSON strings and work with JSON objects in their Scala applications....